
Question #33eb8 - Socratic
First, subtract #color (red) ($145)# from each side of the equation to isolate the #w# term while keeping the equation balanced:
The sum of the first nth term of a geometric series is 145 ... - Socratic
The sum of the first nth term of a geometric series is 145 and the sum of the reciprocal is 145/33. The first term is 1. What is n and the common ratio? Precalculus
An isosceles triangle has sides A, B, and C, such that sides ... - Socratic
12.04 (approx) Let the length of side A or B = x and base is 16. So the height is sqrt [x^2 - (16/2)^2] Now the area of triangle = 1/2 * base * height = 1/2 * 16 * sqrt [x^2 - (16/2)^2]. Therefore, 1/2 * 16 * sqrt …
Solve # { (sqrtx (1-4x-y)=2), (sqrty (1+4x+y)=6):}# - Socratic
No real solutions. Calling alpha = 4x+y we have { (sqrtx (1-alpha)=2), (sqrty (1+alpha)=6):} then 2 alpha = (1+alpha)^2- (1-alpha)^2=36/y-4/x or 4x+y = 9/y-1/x we ...
Question #933a2 - Socratic
Solve: 1. sin x = 0.5623 2. cos x = 0.8963 3. tan x = -2.89 1. Calculator gives --> sin x = 0.5623 --> x = 34.22 and x = 180 - 34.22 = 145.78 deg. Extended answers: x = 34.22 + k360 deg x = 145.78 + k360 …
Can you help me with finding perimeter of this sector fragment?
Aug 26, 2017 · Just Q8. I'll ask more questions if I need more help.
If the measures of a triangle are 90°, 55°, and 3x - Socratic
=> x = 10 The measures (angles) of a triangle sum to 180^o. =>90 + 55 + (3x+5) = 180 =>145 + (3x+5)=180 =>3x + 5 = 35 =>3x = 30 => x = 10
What is the formula for the sequence #4,2,3,4,3,2,...# - Socratic
a_n = 1/120 (3 n^5-40 n^4+145 n^3+40 n^2-868 n+1200) If you want a formula for a sequence with these as the first six terms then you can proceed as follows: Write down the original sequence: color …
Sans the lone satellite Luna, our planet Earth had cleared ... - Socratic
Another (2015 TB 145 ) came a little beyond Moon's maximum apogee distance of 405400 km. In view of all these findings, it is reasonable to admit that the Earth is yet to clear some NEOs like the …
Circle A has a center at # (12 ,9 )# and an area of #16 pi#. Circle B ...
Yes. First we need to find the radii of the circles. We can do this using the formula for area: "Area=pir^2 Circle A pir^2=16pi r^2=16=>r=sqrt(16)=4 Circle B pir^2=67pi r^2=67=>r=sqrt(67) We now find the …